find the distance between the points (5, -3) and (0, 2).

Answer:Distance between points  (5, -3) and (0, 2) is √50 or 7.07Step-by-step explanation:We need to find distance between two points (5,-3) and (0,2)The distance formula used is:[tex]d= \sqrt {\left( { x_2-x_1 } \right)^2 + \left( {y_2-y_1} \right)^2 }[/tex]herex₁= 5, y₁=-3, x₂=0 and y₂=2Putting values in the formula:[tex]d= \sqrt {\left( {x_2-x_1} \right)^2 + \left( {y_2-y_1} \right)^2 }\\d= \sqrt {\left( {0-5} \right)^2 + \left( {2-(-3)} \right)^2 }\\d= \sqrt {\left( {-5} \right)^2 + \left( {2+3} \right)^2 }\\d= \sqrt {25+25}\\d= \sqrt {50}\\d= 7.07[/tex]So, distance between points  (5, -3) and (0, 2) is √50 or 7.07